(1/x)^2-2/x-35=0

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Solution for (1/x)^2-2/x-35=0 equation: 



(1/x)^2-2/x-35=0



Domain of the equation: x)^2!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x!=0

x∈R



We add all the numbers together, and all the variables

(+1/x)^2-2/x-35=0

We calculate fractions


((+1*x)/x^2*x)+(-2x)/x^2*x)-35=0



We calculate terms in parentheses: +((+1*x)/x^2*x), so:

(+1*x)/x^2*x

We add all the numbers together, and all the variables

(+x)/x^2*x

We multiply all the terms by the denominator


(+x)

We get rid of parentheses

x

Back to the equation:

+(x)



We multiply all the terms by the denominator


x*x^2*x)-35+(-2x)=0

Wy multiply elements

x^4*x-2x)=0

We do not support expression: x^4

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